b^2=9/441

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Solution for b^2=9/441 equation:



b^2=9/441
We move all terms to the left:
b^2-(9/441)=0
We add all the numbers together, and all the variables
b^2-(+9/441)=0
We get rid of parentheses
b^2-9/441=0
We multiply all the terms by the denominator
b^2*441-9=0
Wy multiply elements
441b^2-9=0
a = 441; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·441·(-9)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*441}=\frac{-126}{882} =-1/7 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*441}=\frac{126}{882} =1/7 $

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